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Floor Load Capacity Calculator — Joist Size & Safe Loads

Check C24 floor joists against both bending (Eurocode 5) and deflection (span/250), then compare the safe distributed and point loads with your planned use.

Clear span between supports (effective span)

How We Calculate This

This calculator sizes C24 floor joists by the two checks that govern a domestic timber floor: the bending (strength) check to Eurocode 5 and the deflection (serviceability) check. It reports the safe loads and tells you which check is governing.

1. Bending capacity (ULS)

The design moment capacity of each joist is MRd = fm,k × kmod × ksys ÷ γM × (b × h² ÷ 6), using C24 fm,k = 24 N/mm² (BS EN 338), kmod = 0.8, ksys= 1.1 and γM = 1.3. For a 47 × 200 joist this gives MRd = 5.09 kNm.

The applied design moment is M = wULS × Spacing × Span² ÷ 8, where the ULS load wULS = 1.35 × dead + 1.5 × imposed(EN 1990, UK National Annex). The partial factor γM is already inside the capacity, so it is not applied again to the load.

2. Deflection (SLS)

The instantaneous deflection under each characteristic action is δ = 5 × w × L⁴ ÷ (384 × E × I)(unfactored load; E0,mean = 11 kN/mm²). Creep is then added to give the net final deflection wnet,fin = δdead(1 + kdef) + δimposed(1 + ψ2kdef), with kdef= 0.6 (solid timber, service class 1; EC5 Table 3.2) and ψ2 = 0.3 (Category A; BS EN 1990 UK NA).

That final deflection is checked against the span ÷ 250 limit for a floor with a plastered or plasterboard ceiling (NA to BS EN 1995-1-1 Table NA.5). On typical domestic spans deflection usually governs, so the safe distributed load shown is the lower of the bending and deflection checks.

Results are indicative; for final design always confirm against the current TDUK/TRADA span tables or a structural engineer’s calculation.

Frequently Asked Questions

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Last updated: June 2026

Verified against UK standards · estimates only, confirm with your supplier.